On Tue, Jan 27, 2004 at 11:02:25AM -0800, Greg KH wrote:
> On Mon, Jan 26, 2004 at 07:28:03PM -0500, Adrian Drzewiecki wrote:
> > Looking over the code, I noticed something odd in
> > namedev.c:strcmp_pattern() --
> >
> > while (*p && (*p != ']'))
> > p ++;
> > return strcmp_pattern(p+1, s+1);
> >
> > If the pattern string is invalid, and is not terminated by a ']', then 'p'
> > will point at \0 and p+1 will be beyond the string.
>
> Yes, I think you are correct.
>
> Hm, Kay, any idea of the proper way to fix this? I've attached a patch
> below, but I don't think it is correct.
>
> while (*p && (*p != ']'))
> p++;
> - return strcmp_pattern(p+1, s+1);
> + if (*p)
> + return strcmp_pattern(p+1, s+1);
> + else
> + return 1;
> }
> }
Sure, it's perfectly correct. I'm wondering how Adrian found this.
We can use the return 1 at the end of the whole function, and asking
for the closing ']' is more descriptive, but it does the same.
- return strcmp_pattern(p+1, s+1);
+ if (*p == ']')
+ return strcmp_pattern(p+1, s+1);
Patch is attached, that also replaces all the *s with s[0].
/* compare string with pattern (supports * ? [0-9] [!A-Z]) */
static int strcmp_pattern(const char *p, const char *s)
{
- if (*s == '\0') {
- while (*p == '*')
+ if (s[0] == '\0') {
+ while (p[0] == '*')
p++;
- return (*p != '\0');
+ return (p[0] != '\0');
}
- switch (*p) {
+ switch (p[0]) {
case '[':
{
int not = 0;
p++;
- if (*p == '!') {
+ if (p[0] == '!') {
not = 1;
p++;
}
- while (*p && (*p != ']')) {
+ while ((p[0] != '\0') && (p[0] != ']')) {
int match = 0;
if (p[1] == '-') {
- if ((*s >= *p) && (*s <= p[2]))
+ if ((s[0] >= p[0]) && (s[0] <= p[2]))
match = 1;
p += 3;
} else {
- match = (*p == *s);
+ match = (p[0] == s[0]);
p++;
}
if (match ^ not) {
- while (*p && (*p != ']'))
+ while ((p[0] != '\0') && (p[0] != ']'))
p++;
- return strcmp_pattern(p+1, s+1);
+ if (p[0] == ']')
+ return strcmp_pattern(p+1, s+1);
}
}
}
return strcmp_pattern(p+1, s);
return 0;
case '\0':
- if (*s == '\0') {
+ if (s[0] == '\0') {
return 0;
}
break;
default:
- if ((*p == *s) || (*p == '?'))
+ if ((p[0] == s[0]) || (p[0] == '?'))
return strcmp_pattern(p+1, s+1);
break;
}