[PATCH] sched: don't print migration cost when only 1 CPU

If only a single CPU is present, printing this doesn't make much sense.

Signed-off-by: Dave Jones <davej@redhat.com>
Acked-by: Ingo Molnar <mingo@elte.hu>
Acked-by: Nick Piggin <nickpiggin@yahoo.com.au>
Signed-off-by: Andrew Morton <akpm@osdl.org>
Signed-off-by: Linus Torvalds <torvalds@osdl.org>

diff --git a/kernel/sched.c b/kernel/sched.c
index 6b956bd9b49ad46c8e3663e04ec53329cd2bd737..6d7bf55ec33d8f0f80e7b6a00dc720f65ee18de1 100644 (file)
--- a/kernel/sched.c
+++ b/kernel/sched.c
@@ -5977,13 +5977,15 @@ static void calibrate_migration_costs(const cpumask_t *cpu_map)
 #endif
                );
        if (system_state == SYSTEM_BOOTING) {
-               printk("migration_cost=");
-               for (distance = 0; distance <= max_distance; distance++) {
-                       if (distance)
-                               printk(",");
-                       printk("%ld", (long)migration_cost[distance] / 1000);
+               if (num_online_cpus() > 1) {
+                       printk("migration_cost=");
+                       for (distance = 0; distance <= max_distance; distance++) {
+                               if (distance)
+                                       printk(",");
+                               printk("%ld", (long)migration_cost[distance] / 1000);
+                       }
+                       printk("\n");
                }
-               printk("\n");
        }
        j1 = jiffies;
        if (migration_debug)